| ⇦ | 
| ⇨ |
20.0 g of a magnesium carbonate sample decomposes on heating to give CO₂ and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample?
Options
(a) 75
(b) 96
(c) 60
(d) 84
Correct Answer:
84
Explanation:
MgCO₃ -> MgO + CO₂
84 g of MgCO₃ form 40 g of MgO
20g of MgCO₃ form (40 * 20) / 84 g of MgO
= 9.52 g of MgO
Since 8 g of MgO is formed, purity = (8 / 9.52) *100 = 84%
Related Questions: - The absolute enthalpy of neutralisation of the reaction
- Enantiomers
- When river water meets sea water delta formation takes place. This is due to
- Which type of bond is there in H₂S molecules
- Which of the following can act as both oxidising and reducing agents
Question Type: Apply
(15)
Difficulty Level: Moderate
(4)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The absolute enthalpy of neutralisation of the reaction
- Enantiomers
- When river water meets sea water delta formation takes place. This is due to
- Which type of bond is there in H₂S molecules
- Which of the following can act as both oxidising and reducing agents
Question Type: Apply (15)
Difficulty Level: Moderate (4)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply