| ⇦ |
| ⇨ |
Light of wavelength λ is incident on slit of width d. The resulting diffraction pattern is observed on a screen placed at distance D. The linear width of central maximum is equal to width of the slit, then D=……….
Options
(a) 2 λ²/d
(b) d²/2λ
(c) d/λ
(d) 2λ/d
Correct Answer:
d²/2λ
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- A body covers 200 cm in the first 2 seconds and 220 cm in the next 4 seconds.
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- For a simple pendulum performing simple harmonic motion, the time period
- A cyclotron is used to accelerate
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- A body covers 200 cm in the first 2 seconds and 220 cm in the next 4 seconds.
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- For a simple pendulum performing simple harmonic motion, the time period
- A cyclotron is used to accelerate
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply