| ⇦ | 
| ⇨ |
KMnO₄ acts as an oxidising agent in the netural medium and gets reduced to MnO₂. The equivalent weight of KMnO₄ in neutral medium will be
Options
(a) mol wt. /2
(b) mol wt. / 3
(c) mol wt. /4
(d) mol wt. / 7
Correct Answer:
mol wt. / 3
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of the following compounds can exist in optically active form
- Oxidation numbers of P in PO₄³⁻, of S in SO₄²⁻ and that of Cr in Cr₂O₇²⁻
- The oxidation number of nitrogen in HNO₃ is
- Which of the following elements will have the lowest first ionisation energy?
- Carbon atom in C₂(CN)₄ are
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following compounds can exist in optically active form
- Oxidation numbers of P in PO₄³⁻, of S in SO₄²⁻ and that of Cr in Cr₂O₇²⁻
- The oxidation number of nitrogen in HNO₃ is
- Which of the following elements will have the lowest first ionisation energy?
- Carbon atom in C₂(CN)₄ are
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply