| ⇦ | 
| ⇨ |
In Young’s double slit experiment with sodium vapour lamp of wavelength 589 nm and the slits 0.589 mm apart, the half angular width of the central maximum is
Options
(a) sin⁻¹ 0.01
(b) sin⁻¹ 0.0001
(c) sin⁻¹ 0.001
(d) sin⁻¹ 0.1
Correct Answer:
sin⁻¹ 0.001
Explanation:
sin θ = λ / d
= 589 × 10⁻⁹ / 0.589 × 10⁻³ = 10⁻³ = 1 / 1000 = 0.001
Therefore, θ = sin⁻¹ 0.001
Related Questions: - In a uniform circular motion, work done in one complete rotation is
- The work done in which of the following processes is equal to the change in internal energy
- A bomb of mass 16 kg at rest explodes into two pieces of masses of 4 kg and 12 kg.
- The second overtone of an open pipe is in resonance with the first overtone
- The capacitance of two concentric spherical shells of radii R₁ and R₂ (R₂>R₁) is
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a uniform circular motion, work done in one complete rotation is
- The work done in which of the following processes is equal to the change in internal energy
- A bomb of mass 16 kg at rest explodes into two pieces of masses of 4 kg and 12 kg.
- The second overtone of an open pipe is in resonance with the first overtone
- The capacitance of two concentric spherical shells of radii R₁ and R₂ (R₂>R₁) is
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply