⇦ | ⇨ |
In Young’s double slit experiment, when wavelength used is 6000Å and the screen is 40 cm from the slits, the fringes are 0.012 cm wide. What is the distance between the slits?
Options
(a) 0.24 cm
(b) 0.2 cm
(c) 2.4 cm
(d) 0.024 cm
Correct Answer:
0.2 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T)
- The potential energy of a long spring when stretched by 2 cm is U.
- A pellet of mass 1 g is moving with an angular velocity of 1 rad/s along a circle
- One way in which the operation of a n-p-n transistor differs from that of a p-n-p
- A vibration magnetometer placed in magnetic meridian has a small bar magnet
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T)
- The potential energy of a long spring when stretched by 2 cm is U.
- A pellet of mass 1 g is moving with an angular velocity of 1 rad/s along a circle
- One way in which the operation of a n-p-n transistor differs from that of a p-n-p
- A vibration magnetometer placed in magnetic meridian has a small bar magnet
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply