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In Young’s double slit experiment, when wavelength used is 6000Å and the screen is 40 cm from the slits, the fringes are 0.012 cm wide. What is the distance between the slits?
Options
(a) 0.24 cm
(b) 0.2 cm
(c) 2.4 cm
(d) 0.024 cm
Correct Answer:
0.2 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
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