| ⇦ | 
| ⇨ |
In Young’s double slit experiment, the phase difference between the two waves reaching at the location of the third dark fringe is
Options
(a) π
(b) 3π/2
(c) 5π
(d) 3π
Correct Answer:
3π/2
Explanation:
The phase difference in young’s double slit experiment, ɸ=nπ/2
Here, n=3
ɸ=3π/2
Related Questions: - The e.m.f. of a battery is 2 V and its internal resistance is 0.5 Ω. The maximum
- In insulators (CB is Conduction Band and VB is Valence Band)
- In N-type semi-conductor current is due to
- Frequency of stretched string will increase by
- A thin glass(refractive index 1.5) lens has optical power of -5D in air.
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The e.m.f. of a battery is 2 V and its internal resistance is 0.5 Ω. The maximum
- In insulators (CB is Conduction Band and VB is Valence Band)
- In N-type semi-conductor current is due to
- Frequency of stretched string will increase by
- A thin glass(refractive index 1.5) lens has optical power of -5D in air.
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply