In Young’s double slit experiment, the fringe width is 1×10⁻⁴ m, if the distance

In Youngs Double Slit Experiment The Fringe Width Is 1x10 Physics Question

In Young’s double slit experiment, the fringe width is 1×10⁻⁴ m, if the distance between the slit and screen is doubled and the distance between two slits is reduced to half and the wavelength is changed from 6.4×10⁻⁷ m to 4.0×10⁻⁷ m, then the value of new fringe width will be

Options

(a) 2.5×10⁻⁴ m
(b) 2.0×10⁻⁴ m
(c) 1×10⁻⁴ m
(d) 0.5×10⁻⁴ m

Correct Answer:

2.5×10⁻⁴ m

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. Two equal and opposite charges of masses m₁ and m₂ are accelerated
  2. The work done in which of the following processes is zero?
  3. A train is moving along a straight path with uniform acceleration
  4. An atom bomb works on the principle of
  5. When a Daniel cell is connected in the secondary circuit of a potentiometer,

Topics: Wave Optics (101)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*