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In Wheatstone bridge, three resistors P,Q and R are conncected in three arms in order and 4th arm of resistance s, is formed by two resistors s₁ and s₂ connected in parallel. The condition for bridge to be balanced is, P/Q
Options
(a) R(s₁+s₂)/s₁s₂
(b) s₁s₂/R(s₁+s₂)
(c) R(s₁s₂)/(s₁+s₂)
(d) (s₁+s₂)R(s₁s₂)
Correct Answer:
R(s₁+s₂)/s₁s₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 120 m long train is moving in a direction with speed 20 m/s.A train B moving
- The weight of a body on surface of earth is 12.6 N. When it is raised to a height
- There is a ring of radius r having linear charge densityλ and rotating with a uniform
- During mean life of a radioactive element, the fraction that disintegrates is
- The flux linked with a circuit is given by φ=t³+3t-7. The graph between time
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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