| ⇦ | 
| ⇨ |
In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted respectively?
Options
(a) 3,5
(b) 5,3
(c) 3,3
(d) 3,1
Correct Answer:
3,1
Explanation:
Change in A = 234 – 222 = 12
This is the effect of 3 α-particles = 3 × ₂He⁴
Change in Z due to 3α = -6
Given change in Z = 87 – 92 = -5
Hence one beta is emitted = -6 + 1 = -5
Therefore, 3α and 1β
Related Questions: - A steady current of 1.5 amp flows through a copper voltmeter for 10 minutes
- Length of a conductor is 50 cm radius of cross section 0.1 cm and resistivity
- Consider two nuclei of the same radioactive nuclide. One of the nuclei was created
- A coil of N turns and mean cross-sectional area A is rotating with uniform angular
- In the Young’s modulus experiment, if length of wire and radius both are doubled,
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A steady current of 1.5 amp flows through a copper voltmeter for 10 minutes
- Length of a conductor is 50 cm radius of cross section 0.1 cm and resistivity
- Consider two nuclei of the same radioactive nuclide. One of the nuclei was created
- A coil of N turns and mean cross-sectional area A is rotating with uniform angular
- In the Young’s modulus experiment, if length of wire and radius both are doubled,
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply