| ⇦ | 
| ⇨ |
In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted respectively?
Options
(a) 3,5
(b) 5,3
(c) 3,3
(d) 3,1
Correct Answer:
3,1
Explanation:
Change in A = 234 – 222 = 12
This is the effect of 3 α-particles = 3 × ₂He⁴
Change in Z due to 3α = -6
Given change in Z = 87 – 92 = -5
Hence one beta is emitted = -6 + 1 = -5
Therefore, 3α and 1β
Related Questions: - The half-life of a radioactive substance is 30 min. The time (in minutes) taken
- A body is moving in a vertical circle. The string must remain taut at the highest point
- A particle of mass M is suited at the centre of a spherical shell of same mass and radius
- Energy of photon whose frequency is 10¹² MHz will be
- If a mass of 20g having charge 3.0 mC moving with velocity 20ms⁻¹ enters a region
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The half-life of a radioactive substance is 30 min. The time (in minutes) taken
- A body is moving in a vertical circle. The string must remain taut at the highest point
- A particle of mass M is suited at the centre of a spherical shell of same mass and radius
- Energy of photon whose frequency is 10¹² MHz will be
- If a mass of 20g having charge 3.0 mC moving with velocity 20ms⁻¹ enters a region
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply