| ⇦ |
| ⇨ |
In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted respectively?
Options
(a) 3,5
(b) 5,3
(c) 3,3
(d) 3,1
Correct Answer:
3,1
Explanation:
Change in A = 234 – 222 = 12
This is the effect of 3 α-particles = 3 × ₂He⁴
Change in Z due to 3α = -6
Given change in Z = 87 – 92 = -5
Hence one beta is emitted = -6 + 1 = -5
Therefore, 3α and 1β
Related Questions: - In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency
- A series combination of n₁ capacitors, each of value C₁, is charged by a source
- The Bohr model of atoms
- Electromagnets are made of soft iron because soft iron has
- Two wires of equal length and equal diameter and having resistivities ρ₁ and ρ₂
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency
- A series combination of n₁ capacitors, each of value C₁, is charged by a source
- The Bohr model of atoms
- Electromagnets are made of soft iron because soft iron has
- Two wires of equal length and equal diameter and having resistivities ρ₁ and ρ₂
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply