| ⇦ | 
| ⇨ |
In the electrolysis of water, one faraday of electrical energy would evolve
Options
(a) one mole of oxygen
(b) one g atom of oxygen
(c) 8 g of oxygen
(d) 22.4 litres of oxygen
Correct Answer:
8 g of oxygen
Explanation:
Hydrolysis of water can be represented by the following equations: 2H₂O ⇌ O₂ + 4H⁺ + 4e⁻. 4 Faraday of charge liberate O₂ = 32 g. Therefore 1 Faraday of charge liberate O₂ = 32/4 = 8g.
Related Questions: - Oxidation number of iodine in IO₃⁻, IO₄⁻, KI and I₂ respectively are
- In dichromate dimer
- The amount of copper deposited by one Faraday current will be maximum in an
- In the commercial gasolines,the type of hydrocarbons which are more desirable is
- Which of the following is more acidic in nature
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Oxidation number of iodine in IO₃⁻, IO₄⁻, KI and I₂ respectively are
- In dichromate dimer
- The amount of copper deposited by one Faraday current will be maximum in an
- In the commercial gasolines,the type of hydrocarbons which are more desirable is
- Which of the following is more acidic in nature
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply