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In the electrolysis of water, one faraday of electrical energy would evolve
Options
(a) one mole of oxygen
(b) one g atom of oxygen
(c) 8 g of oxygen
(d) 22.4 litres of oxygen
Correct Answer:
8 g of oxygen
Explanation:
Hydrolysis of water can be represented by the following equations: 2H₂O ⇌ O₂ + 4H⁺ + 4e⁻. 4 Faraday of charge liberate O₂ = 32 g. Therefore 1 Faraday of charge liberate O₂ = 32/4 = 8g.
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Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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