| ⇦ | 
| ⇨ |
In the brown ring test for the nitrate ion, the brown colour is due to
Options
(a) [Fe(H₂O)₅NO]²⁺
(b) [Fe(H₂O)₅NO]³⁺
(c) [Fe(H₂O)₆]⁺
(d) [Fe(H₂O)₅NO₂]²⁺
Correct Answer:
[Fe(H₂O)₅NO]²⁺
Explanation:
When an aqueous solution of the nitrate salt is treated with freashly prepared solution of ferrous sulphate and concentrated H₂SO₄, a brown ring is formed on account of the formation of complex [Fe(H₂O)₅NO]SO₄ at the junction of two liquids. NaNO₃ + H₂SO₄ → NaHSO₄ + HNO₃. 6FeSO₄ + 2HNO₃ + 3H₂SO₄ → 3Fe₂(SO₄)₃ + 4H₂O + 2NO. [Fe(H₂O)₆]SO₄.H₂O + NO → [Fe(H₂O)₅NO]SO₄ + 2H₂O(brown ring).
Related Questions: - Reaction of methyl bromide with aqueous sodium hydroxide involves
- If the gas at constant temperature and pressure expands, then its
- Ostwald’s dilution law is applicable to only
- The electronic configuration of a noble gas is
- If 1 mole of an ideal gas expands isothermally at 37⁰C from 15 litres
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Reaction of methyl bromide with aqueous sodium hydroxide involves
- If the gas at constant temperature and pressure expands, then its
- Ostwald’s dilution law is applicable to only
- The electronic configuration of a noble gas is
- If 1 mole of an ideal gas expands isothermally at 37⁰C from 15 litres
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply