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In the Bohr’s model of hydrogen atom, the ratio of the kinetic energy to the total energy of the electron in nth quantum state is
Options
(a) (-1)
(b) (+1)
(c) (-2)
(d) (+2)
Correct Answer:
(-1)
Explanation:
In Bohr’s model of hydrogen atom, the kinetic energy of the electron in nᵗʰ state is given by
K = me⁴ / 8ε₀²h²n² = (13.6 / n²) eV
where, me⁴ / 8ε₀²h² = 13.6 eV
The potential energy of electron in nᵗʰ state is given by
U = -2me⁴ / 8ε₀²h²n² = (-27.2 / n²) eV
Total energy of electron in nᵗʰ state is given by
E = K + U = (me⁴ / 8ε₀²h²n² ) – (2me⁴ / 8ε₀²h²n²)
E = -me⁴ / 8ε₀²h²n² = (-13.6 / n ²) eV
.·. K / E = -1
Related Questions: - A light of wavelength 5000Å falls on a sensitive plate with photoelectric work
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A light of wavelength 5000Å falls on a sensitive plate with photoelectric work
- An electron in hydrogen atom makes a transition n₁ → n₂
- Monochromatic radiation emitted when electron on hydrogen atom
- A rectangular copper coil is placed in a uniform magnetic field of induction 40 mT
- Two charges each equal to 2µ C are 0.5m apart. If both of them exist inside vacuum
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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