⇦ | ⇨ |
In Ramsay and Rayleigh’s isolation on noble gases from air, the nitrogen of the air is finally converted into
Options
(a) NaNO₂ only
(b) NO and NO₂
(c) NaNO₃ only
(d) NaNO₂ and NaNO₃
Correct Answer:
NaNO₂ and NaNO₃
Explanation:
Nitrogen is finally converted into NaNO₂ and NaNO₃, in Ramsay and Rayleigh’s method. N₂ + O₂ → 2NO. 2NO + O₂ → 2NO₂. 2NO₂ + 2NaOH → NaNO₂ + NaNO₃ + H₂O.
Related Questions: - CCl₄ and freons
- In the brown ring test for the nitrate ion, the brown colour is due to
- Oxidation state of osmium(Os) in OsO₄ is
- Which is the correct order of increasing energy of the listed orbitals in the atom
- Volume of 0.1 M K₂Cr₂O₇ required to oxidize 35 mL of 0.5 M FeSO₄ solution is
Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- CCl₄ and freons
- In the brown ring test for the nitrate ion, the brown colour is due to
- Oxidation state of osmium(Os) in OsO₄ is
- Which is the correct order of increasing energy of the listed orbitals in the atom
- Volume of 0.1 M K₂Cr₂O₇ required to oxidize 35 mL of 0.5 M FeSO₄ solution is
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply