| ⇦ |
| ⇨ |
In P-N junction having depletion layer of thickness 10⁻⁶ m, the potential across it is 0.1 V. The electric field is
Options
(a) 10⁷
(b) 10⁻⁶
(c) 10⁵
(d) 10⁻⁵
Correct Answer:
10⁵
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The radius of orbit of a planet is two times that of the earth. The time period
- A satellite S is moving in an elliptical orbit around the earth. The mass
- 4.0 g of a gas occupies 22.4 litres at NTP. The specific heat capacity of the gas
- A particle executing simple harmonic motion of amplitude 5 cm has maximum
- The moment of inertia of a thin uniform rod of mass M and length L about an axis
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The radius of orbit of a planet is two times that of the earth. The time period
- A satellite S is moving in an elliptical orbit around the earth. The mass
- 4.0 g of a gas occupies 22.4 litres at NTP. The specific heat capacity of the gas
- A particle executing simple harmonic motion of amplitude 5 cm has maximum
- The moment of inertia of a thin uniform rod of mass M and length L about an axis
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

As we know;
|dV|=E.d
dV-> barrier voltage
E-> barrier field
d-> depletion region
So, E = 0.1V/10^-6m
E = 10^5 V/m