| ⇦ |
| ⇨ |
In L-C-R series circuit, an alternating emf e and current i are given by the equations e=100 sin (100t) V.
i=100 sin(100t+π/3)mA .
The average power dissipated in the circuit will be
Options
(a) 100 W
(b) 10 W
(c) 5 W
(d) 2.5 W
Correct Answer:
2.5 W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two radiations of photons energies 1 eV and 2.5 eV, successively
- A particle moves from position r₁ = 3i + 2j -6k to position r₂ = 14i + 13 j+ 9 k
- The mean distance between the atoms of iron is 3 x 10⁻¹⁰ m and interatomic force
- What is the Q-value of the reaction?
¹H+⁷Li→⁴He+⁴He
- Energy bands in solids are a consequence of
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two radiations of photons energies 1 eV and 2.5 eV, successively
- A particle moves from position r₁ = 3i + 2j -6k to position r₂ = 14i + 13 j+ 9 k
- The mean distance between the atoms of iron is 3 x 10⁻¹⁰ m and interatomic force
- What is the Q-value of the reaction? ¹H+⁷Li→⁴He+⁴He
- Energy bands in solids are a consequence of
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply