| ⇦ |
| ⇨ |
In L-C-R series circuit, an alternating emf e and current i are given by the equations e=100 sin (100t) V.
i=100 sin(100t+π/3)mA .
The average power dissipated in the circuit will be
Options
(a) 100 W
(b) 10 W
(c) 5 W
(d) 2.5 W
Correct Answer:
2.5 W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A charge of 100 μC has a potential at a distance of 9 m is
- Three identical spheres, each of mass 3 kg are placed touching each other
- A particle of mass m moves with constant speed along a circular path of radius r under
- A parallel plate air capacitor of capacitance C is connected to a cell of emf
- A bus is moving with a velocity of 5 ms⁻¹ towards a huge wall.
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A charge of 100 μC has a potential at a distance of 9 m is
- Three identical spheres, each of mass 3 kg are placed touching each other
- A particle of mass m moves with constant speed along a circular path of radius r under
- A parallel plate air capacitor of capacitance C is connected to a cell of emf
- A bus is moving with a velocity of 5 ms⁻¹ towards a huge wall.
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply