| ⇦ | 
| ⇨ |
In Cu-ammonia complex, the state of hybridization of Cu²⁺ is
Options
(a) sp³
(b) d³
(c) sp²f
(d) dsp²
Correct Answer:
dsp²
Explanation:
Square planar complex is formed by dsp² hybridisation.
Related Questions: - CO₂ is liberated on adding sodium carbonate to a carboxylic acid.The carbon
- Of the following 0.10 m aqueous solution which one will exhibit the largest freezing
- When iodine is dissolved in CCl₄, the resulting colour is
- By which of the following processes permanent hardness of water can be removed
- Which of the following shows bond in silicone?
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- CO₂ is liberated on adding sodium carbonate to a carboxylic acid.The carbon
- Of the following 0.10 m aqueous solution which one will exhibit the largest freezing
- When iodine is dissolved in CCl₄, the resulting colour is
- By which of the following processes permanent hardness of water can be removed
- Which of the following shows bond in silicone?
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply