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In Cu-ammonia complex, the state of hybridization of Cu²⁺ is
Options
(a) sp³
(b) d³
(c) sp²f
(d) dsp²
Correct Answer:
dsp²
Explanation:
Square planar complex is formed by dsp² hybridisation.
Related Questions: - When sodium benzoate reacts with sodalime what is produced
- The most probable radius (in pm) for finding the electron in He⁺ is
- 6.02 x 10²° molecules of urea are present in 100 mL of its solution
- During the decomposition of H₂O₂ to give oxygen, 48 g O₂ is formed per minute
- Which of the following acts as an oxidising as well as reducing agent
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When sodium benzoate reacts with sodalime what is produced
- The most probable radius (in pm) for finding the electron in He⁺ is
- 6.02 x 10²° molecules of urea are present in 100 mL of its solution
- During the decomposition of H₂O₂ to give oxygen, 48 g O₂ is formed per minute
- Which of the following acts as an oxidising as well as reducing agent
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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