| ⇦ |
| ⇨ |
In Cu-ammonia complex, the state of hybridization of Cu²⁺ is
Options
(a) sp³
(b) d³
(c) sp²f
(d) dsp²
Correct Answer:
dsp²
Explanation:
Square planar complex is formed by dsp² hybridisation.
Related Questions: - Ethyl iodide when heated with sodium in dry ether gives pure
- In which of the following compounds, carbon exhibits a valency of 4
- The oxidation states of Mn in MnSO₄,MnO₂,K₂MnO₄ and KMnO₄ are respectively
- Which of the following C-H bonds has lowest bond dissociation energy
- For two ionic solids CaO and KI,identify the wrong statements among the following
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ethyl iodide when heated with sodium in dry ether gives pure
- In which of the following compounds, carbon exhibits a valency of 4
- The oxidation states of Mn in MnSO₄,MnO₂,K₂MnO₄ and KMnO₄ are respectively
- Which of the following C-H bonds has lowest bond dissociation energy
- For two ionic solids CaO and KI,identify the wrong statements among the following
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply