⇦ | ⇨ |
In Cu-ammonia complex, the state of hybridization of Cu²⁺ is
Options
(a) sp³
(b) d³
(c) sp²f
(d) dsp²
Correct Answer:
dsp²
Explanation:
Square planar complex is formed by dsp² hybridisation.
Related Questions: - For a reaction, 2NOCl(g) + Cl₂(g) , Kc at 427⁰C is 3 ˣ 10⁻⁶ L.mol⁻¹.
- 1-bromopropane on treatment with ethanolic potassium hydroxide produces
- The cylindrical shape of an alkyne is due to
- Nitrobenzene gives N-phenylhydroxylamine by
- Strong reducing behaviour of H₃PO₂ is due to
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For a reaction, 2NOCl(g) + Cl₂(g) , Kc at 427⁰C is 3 ˣ 10⁻⁶ L.mol⁻¹.
- 1-bromopropane on treatment with ethanolic potassium hydroxide produces
- The cylindrical shape of an alkyne is due to
- Nitrobenzene gives N-phenylhydroxylamine by
- Strong reducing behaviour of H₃PO₂ is due to
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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