| ⇦ |
| ⇨ |
In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to
Options
(a) 4 L
(b) 2 L
(c) L/2
(d) L/4
Correct Answer:
L/2
Explanation:
At resonance ω = 1 / √(LC)
Since ω is constant,
Therefore, LC = L’C’ = L’ × 2C
⇒ L’ = L / 2
Related Questions: - Which of the following substances has the highest elasticity?
- The dimensional formula for Boltzmann’s constant is
- The intensity of magnetisation of a bar magnet is 5×10⁴ Am⁻¹. The magnetic length
- Consider a two particle system with particle having masses m₁ and m₂. If the first
- For principal quantum number n=3, the possible values of orbital quantum number
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following substances has the highest elasticity?
- The dimensional formula for Boltzmann’s constant is
- The intensity of magnetisation of a bar magnet is 5×10⁴ Am⁻¹. The magnetic length
- Consider a two particle system with particle having masses m₁ and m₂. If the first
- For principal quantum number n=3, the possible values of orbital quantum number
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply