| ⇦ | 
| ⇨ |
In an inductor when current changes from 2 A to 18 A in 0.05 sec, the e.m.f. induced is 20 V. The inductance L is
Options
(a) 62.5 mH
(b) 625 mH
(c) 6.25 mH
(d) 0.625 mH
Correct Answer:
62.5 mH
Explanation:
Induced e.m.f. |e| = L (dI / dt) = L(18 – 2) / 0.05 or,
L = (20 × 0.05) / 16 = 0.0625 H = 62.5 mH
Related Questions: - Dispersion of light is caused due to
- With the decrease of current in the primary coil from 2 amperes to zero value
- The minimum wavelength of X-rays produced in a Collidge tube operated
- A beam of light of wavelength 590 nm is focussed by a converging lens of diameter
- An object is attached to the bottom of a light vertical spring and set vibrating.
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Dispersion of light is caused due to
- With the decrease of current in the primary coil from 2 amperes to zero value
- The minimum wavelength of X-rays produced in a Collidge tube operated
- A beam of light of wavelength 590 nm is focussed by a converging lens of diameter
- An object is attached to the bottom of a light vertical spring and set vibrating.
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply