In an ac circuit an alternating voltage e = 200 √2 sin 100 t volts is connected

In an ac circuit an alternating voltage e = 200 √2 sin 100 t volts is connected to a capacitor of capacity 1 µF. The r.m.s. value of the current in the circuit is

Options

(a) 10 mA
(b) 100 mA
(c) 200 mA
(d) 20 mA

Correct Answer:

20 mA

Explanation:

Vᵣₘₛ = 200 √2 / √2 = 200 V
Iᵣₘₛ = Vᵣₘₛ / Xc = 200/1 / 100 x 10⁻⁶
= 2 x 10⁻² = 20 mA

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