| ⇦ | 
| ⇨ |
In an ac circuit an alternating voltage e = 200 √2 sin 100 t volts is connected to a capacitor of capacity 1 µF. The r.m.s. value of the current in the circuit is
Options
(a) 10 mA
(b) 100 mA
(c) 200 mA
(d) 20 mA
Correct Answer:
20 mA
Explanation:
Vᵣₘₛ = 200 √2 / √2 = 200 V
Iᵣₘₛ = Vᵣₘₛ / Xc = 200/1 / 100 x 10⁻⁶
= 2 x 10⁻² = 20 mA
Related Questions: - The control rods used in a nuclear reactor can be made up of
- A galvanometer acting as a voltmeter will have
- Pascal-second has the dimensions of
- Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series
- The potential energy of a simple harmonic oscillator when the particle is half way
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The control rods used in a nuclear reactor can be made up of
- A galvanometer acting as a voltmeter will have
- Pascal-second has the dimensions of
- Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series
- The potential energy of a simple harmonic oscillator when the particle is half way
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
10^-6 is wrong it will be 10*10^-6=10^-5 so correct answer 200mA
V(rms) = 200 √2 / √2 = 200 V
I(rms) = V(rms) / Xc = (200/1) / (100 x 10⁻⁶)
= 2 x 10⁻² = 20 mA