| ⇦ | 
| ⇨ |
In acidic medium, H₂O₂ changes Cr₂O₇²⁻ to CrO₅ which has two ( -O – O -) bonds. Oxidation state of Cr in CrO₅ is
Options
(a) 5
(b) 3
(c) 6
(d) -10
Correct Answer:
6
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two miscible liquids can be separated by
- The correct order of acidic strength is
- Vanadium (III) oxide is a strong
- What is formed when nitrobenzene is reduced using zinc and alkali
- Which one of the following moleculescontains no π bond?
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two miscible liquids can be separated by
- The correct order of acidic strength is
- Vanadium (III) oxide is a strong
- What is formed when nitrobenzene is reduced using zinc and alkali
- Which one of the following moleculescontains no π bond?
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply