| ⇦ |
| ⇨ |
In a radioactive decay process, the negatively charged emitted β- particles are
Options
(a) the electrons produced as a result of the decay of neutrons inside the nucleus
(b) the electrons produced as a result of collisions between atoms
(c) the electrons orbiting around the nucleus
(d) the electrons present inside the nucleus
Correct Answer:
the electrons produced as a result of the decay of neutrons inside the nucleus
Explanation:
In beta minus decay (β⁻), a neutron is transformed into a proton, and an electronis emitted from the nucleus along with antineutrino.
n = p + e⁻ + v⁻
Related Questions: - A radioactive substance has a half-life of four months. Three-fourth of substance
- The molar specific heats of an ideal gas at constant pressure and volume are denoted
- The potential energy of particle in a force field is U = A/r² – b/r, where A and B
- A force of 10 newton acts on a body of mass 20 kg for 10 seconds. Change in its momentum
- An object is placed at a distance of 10 cm from a co-axial combination of two lenses
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A radioactive substance has a half-life of four months. Three-fourth of substance
- The molar specific heats of an ideal gas at constant pressure and volume are denoted
- The potential energy of particle in a force field is U = A/r² – b/r, where A and B
- A force of 10 newton acts on a body of mass 20 kg for 10 seconds. Change in its momentum
- An object is placed at a distance of 10 cm from a co-axial combination of two lenses
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply