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In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The distance of the closest approach of an alpha particle fired at a nucleus
- For the normal eye, the cornea of eye provides a converging power of 40D
- The value of coefficient of volume expansion of glycerin is 5 x 10⁻⁴ k⁻¹.
- By sucking through a straw, a student can reduce the pressure of his lungs
- The acceleration due to gravity near the surface of a planet of radius R and density d
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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