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In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two metal spheres of radii 0.01m and 0.02m are given a charge of 15mC and 45mC
- A body is thrown with a velocity of 9.8 m/s making angle of 30° with the horizontal
- A beam of light consisting of red, green and blue colours is incident on a right
- The mean radius of the earth is R, its angular speed on its own axis is ?
- A stationary particle explodes into two particles of masses m₁ and m₂ which move
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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