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In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The voltage gain of an amplifier with 9% negative feedback is 10.
- According to Hook’s law of elasticity, if stress is increased, the ratio of stress
- The electric current in AC circuit is given by the relation i-3 sinωt+4 cos ωt.
- The rest mass of a body is m1. It moves with a velocity of 0.6c, then its relativistic
- A step-up transformer operates on a 230 V line and supplies a current of 2 A.
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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