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In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Radii of curvature of a converging lens are in the rato 1:2. Its focal length
- An amplifier has a voltage gain Av=1000. The voltage gain in dB is
- The radius of the convex surface of a plano-convex lens is 20 cm and the refractive index
- An electron of mass m and a photon have same energy E. The ratio of de-Broglie
- A body is placed in an insulating container at temperature 227⁰C.
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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