| ⇦ | 
| ⇨ |
In a buffer solution containing equal concentration of B⁻ and HB, the Kb for B⁻ is 10⁻¹⁰.The pH of buffer solution is
Options
(a) 10
(b) 7
(c) 6
(d) 4
Correct Answer:
4
Explanation:
We know, pOH = pK(b) + log{[B⁻]/[HB]},
Since, [B⁻] = [HB] (given).
Therefore pOH = pK(b) ⇒ pOH = 10,
Therefore pH = 14 – 10 = 4.
Related Questions: - Tollen’s test can be used to distinguish
- Oxidation of acetaldehyde with selenium dioxide produces
- When ethanal is treated with Fehling’s solution. it gives a precipitate of
- Dumas method involves the determination of nitrogen content in the organic
- Difference in density is the basis of
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Tollen’s test can be used to distinguish
- Oxidation of acetaldehyde with selenium dioxide produces
- When ethanal is treated with Fehling’s solution. it gives a precipitate of
- Dumas method involves the determination of nitrogen content in the organic
- Difference in density is the basis of
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply