| ⇦ |
| ⇨ |
If ∆U and ∆W represent the increase in internal energy and work done by the system respectively in a thermodynamical process, which of the following is true?
Options
(a) ∆U = – ∆W, in an adiabatic process
(b) ∆U = ∆W, in an isothermal process
(c) ∆U = ∆W, in an adiabatic process
(d) ∆U = – ∆W, in an isothermal process
Correct Answer:
∆U = – ∆W, in an adiabatic process
Explanation:
BY first law of thermodynamics, ∆Q = ∆U + ∆W
In adiabatic process, ∆Q = 0 ∆U = – ∆W
In isothermal process, ∆U = 0 ∆Q = ∆W
Related Questions: - Pascal-second has the dimensions of
- If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,
- Unit of electrical conductivity is
- Perfectly black body radiates the energy 18 J/s at 300K. Another ordinary body of e=0.8
- A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pascal-second has the dimensions of
- If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,
- Unit of electrical conductivity is
- Perfectly black body radiates the energy 18 J/s at 300K. Another ordinary body of e=0.8
- A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply