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If ∆U and ∆W represent the increase in internal energy and work done by the system respectively in a thermodynamical process, which of the following is true?
Options
(a) ∆U = – ∆W, in an adiabatic process
(b) ∆U = ∆W, in an isothermal process
(c) ∆U = ∆W, in an adiabatic process
(d) ∆U = – ∆W, in an isothermal process
Correct Answer:
∆U = – ∆W, in an adiabatic process
Explanation:
BY first law of thermodynamics, ∆Q = ∆U + ∆W
In adiabatic process, ∆Q = 0 ∆U = – ∆W
In isothermal process, ∆U = 0 ∆Q = ∆W
Related Questions: - An adiabatic process occurs at constant
- If in a p-n junction, a square input signal of 10 V is applied as shown, then the output
- If an electron and a proton have the same de-Broglie wavelength, then the kinetic
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An adiabatic process occurs at constant
- If in a p-n junction, a square input signal of 10 V is applied as shown, then the output
- If an electron and a proton have the same de-Broglie wavelength, then the kinetic
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- The name of ions knocked out from the hot surface is
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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