| ⇦ | 
| ⇨ |
If voltage across a bulb rated 220 volt-100 Watt drops by 2.5% of its rated value, the percentage of the rated value by which the power would decrease is:
Options
(a) 20%
(b) 2.50%
(c) 5%
(d) 10%
Correct Answer:
5%
Explanation:
Resistance of bulb is constant
P = V² / R
∆p / p = 2∆V / V + ∆R / R
∆p / P = 2 x 2.5 + 0 = 5%
Related Questions: - The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- In Young’s double slit experiment, for which colour the fringe width is the least
- If a nucleus ᴢXᴬ emits 9α and 5β-particles, then the ratio of total protons and neutrons
- There is a ring of radius r having linear charge densityλ and rotating with a uniform
- The height at which the weight of a body becomes 1/16 th, its weight
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- In Young’s double slit experiment, for which colour the fringe width is the least
- If a nucleus ᴢXᴬ emits 9α and 5β-particles, then the ratio of total protons and neutrons
- There is a ring of radius r having linear charge densityλ and rotating with a uniform
- The height at which the weight of a body becomes 1/16 th, its weight
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply