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If voltage across a bulb rated 220 volt-100 Watt drops by 2.5% of its rated value, the percentage of the rated value by which the power would decrease is:
Options
(a) 20%
(b) 2.50%
(c) 5%
(d) 10%
Correct Answer:
5%
Explanation:
Resistance of bulb is constant
P = V² / R
∆p / p = 2∆V / V + ∆R / R
∆p / P = 2 x 2.5 + 0 = 5%
Related Questions: - An ideal gas is expanding such that PT²=constant. The coefficient of volume
- A parallel plate air capacitor is charged to a potential difference of V volts.
- The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
- Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
- If a given volume of water in a 220V heater is boiled in 5 min, then same volume
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An ideal gas is expanding such that PT²=constant. The coefficient of volume
- A parallel plate air capacitor is charged to a potential difference of V volts.
- The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
- Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
- If a given volume of water in a 220V heater is boiled in 5 min, then same volume
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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