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If the self inductance of 500 turn coil is 125 mH, then the self inductance of similar coil of 800 turns is
Options
(a) 48.4 mH
(b) 200 mH
(c) 187.5 mH
(d) 320 mH
Correct Answer:
320 mH
Explanation:
Self inductance of a coil, L = μᵣμ₀n² Al
Where μᵣ is the relative permittivity of the coil, n is the number of terms per unit length, A is the area of cross-section, l is the length of the solenoid
L ∝ n²
Self inductance of 500 turns coil = 125 mH Therefore, L for the coil of 800 turns = [125 / (500)²] × 800² L = 320 mH
Related Questions: - A silver wire of radius 0.1 cm carries a current of 2A. If the charge density in silver
- Light of wavelength λ is incident on slit of width d. The resulting diffraction
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A silver wire of radius 0.1 cm carries a current of 2A. If the charge density in silver
- Light of wavelength λ is incident on slit of width d. The resulting diffraction
- Which of the following rods of same material undergoes maximum elongation
- On adjusting the P-N junction diode in forward bias,
- The de-Broglie wavelength of an electron is the same as that of a 50 KeV X-ray photon.
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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