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If the ratio of the rates of diffusion of two gases A and B is 4 : 1. Then the ratio of their densities in the same order is
Options
(a) 16 : 1
(b) 4 : 1
(c) 1 : 4
(d) 1 : 16
Correct Answer:
1 : 16
Explanation:
Rate of diffusion ∝ 1 / √d. rA / rB = √dB / dA ⇒ 4 / 1 = √dB / dA ⇒ 16 / 1 = dB / dA ⇒ dA / dB = 1 / 16.
Related Questions: - Which of the following indicator is known as metal indicator
- Oxidation state of osmium(Os) in OsO₄ is
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Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following indicator is known as metal indicator
- Oxidation state of osmium(Os) in OsO₄ is
- Phenylethyl ether when boiled with concentrated HBr gives
- A molal solution is one that contains one mole of a solute in
- In Kjeldahl’s method,ammonia from 5g of food neutralizes 30 cm3 of 0.1 N acid.
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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According to Graham’s law of diffusion,
RA/RB=√dB/dA
or,(4/1)2=dB/dA
or,16/1=dB/dA
or,dA:dB= 1:16