| ⇦ | 
| ⇨ |
If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum intensity and minimum intensity is
Options
(a) (9:1)
(b) (1:9)
(c) (4:1)
(d) (1:4)
Correct Answer:
(9:1)
Explanation:
Let ɑ and b the amplitude of wave.
Given: ɑ / b = 2 / 1 (or) ɑ = 2b
I(max) / I(min) = (ɑ + b)² / (ɑ – b)² = 9 / 1
Related Questions: - An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
- What are the unit of K = 1 / (4 π ?￢ﾂﾒ)
- An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- A fringe width of a certain interference pattern is β=0.002 cm. What is the distance
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
- What are the unit of K = 1 / (4 π ?￢ﾂﾒ)
- An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- A fringe width of a certain interference pattern is β=0.002 cm. What is the distance
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply