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If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum intensity and minimum intensity is
Options
(a) (9:1)
(b) (1:9)
(c) (4:1)
(d) (1:4)
Correct Answer:
(9:1)
Explanation:
Let ɑ and b the amplitude of wave.
Given: ɑ / b = 2 / 1 (or) ɑ = 2b
I(max) / I(min) = (ɑ + b)² / (ɑ – b)² = 9 / 1
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- Van der waals,equation of state is(p+a/v²)(V-b)=nRT. The dimensions of a and b
- The maximum wavelength of radiations emitted at 900K is 4 µm. What will be the maximum
- Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube.
- If 20% of a radiactive element decays in 10 days, then amount of original material left
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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