| ⇦ | 
| ⇨ |
If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume is decreases by 10% at constant temperature then the bulk modulus of the gas is
Options
(a) 15.5×10⁵ Pa
(b) 1.4×10⁵ Pa
(c) 1.55×10⁵ Pa
(d) 0.0155×10⁵ Pa
Correct Answer:
1.55×10⁵ Pa
Explanation:
Bulk modulus = normal stress / volumetric strain
= (F/A) / (-∆V/V) = -(PV / ∆V)
For an isothermal process, PV = constant
So, PdV + VdP = 0 ⇒ (-VdP / dV) = P
B = (-VdP / dV) = (100 / 10) × (1.165 × 10⁵ – 1.01 × 10⁵)
= 1.55 × 10⁵ Pa.
Related Questions: - If the electric field lines is flowing along axis of a cylinder, then the flux
- A beam of light of wavelength 590 nm is focussed by a converging lens of diameter
- The de-Broglie wavelength of an electron having 80 eV of energy is nearly
- Curie temperature above which
- Which series of hydrogen spectrum corresponds to ultraviolet region?
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the electric field lines is flowing along axis of a cylinder, then the flux
- A beam of light of wavelength 590 nm is focussed by a converging lens of diameter
- The de-Broglie wavelength of an electron having 80 eV of energy is nearly
- Curie temperature above which
- Which series of hydrogen spectrum corresponds to ultraviolet region?
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply