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If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume is decreases by 10% at constant temperature then the bulk modulus of the gas is
Options
(a) 15.5×10⁵ Pa
(b) 1.4×10⁵ Pa
(c) 1.55×10⁵ Pa
(d) 0.0155×10⁵ Pa
Correct Answer:
1.55×10⁵ Pa
Explanation:
Bulk modulus = normal stress / volumetric strain
= (F/A) / (-∆V/V) = -(PV / ∆V)
For an isothermal process, PV = constant
So, PdV + VdP = 0 ⇒ (-VdP / dV) = P
B = (-VdP / dV) = (100 / 10) × (1.165 × 10⁵ – 1.01 × 10⁵)
= 1.55 × 10⁵ Pa.
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Topics: Thermodynamics
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A boat of mass 40 kg is at rest.A dog of mass 4 kg moves in the boat
- By the succesive disintegration of ₉₂U²³⁸, the final product obtained is ₈₂Pb²⁰⁶, then
- A train of mass 2x 10⁵ kg has a constant speed of 20 m/s up a hill inclined
- A 1 kg particle strikes a wall with velocity 1 m/s at an angle 30° and reflects
- A block of mass m moving at a velocity v collides with another block of mass 2m
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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