If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume

If The Pressure Of Gas Is Increased From 101x10 Pa Physics Question

If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume is decreases by 10% at constant temperature then the bulk modulus of the gas is

Options

(a) 15.5×10⁵ Pa
(b) 1.4×10⁵ Pa
(c) 1.55×10⁵ Pa
(d) 0.0155×10⁵ Pa

Correct Answer:

1.55×10⁵ Pa

Explanation:

Bulk modulus = normal stress / volumetric strain
= (F/A) / (-∆V/V) = -(PV / ∆V)
For an isothermal process, PV = constant
So, PdV + VdP = 0 ⇒ (-VdP / dV) = P
B = (-VdP / dV) = (100 / 10) × (1.165 × 10⁵ – 1.01 × 10⁵)
= 1.55 × 10⁵ Pa.

Related Questions:

  1. Light of wavelength λ from a point source falls on a small circular obstacle
  2. If Q, E and W denote respectively the heat added, change in internal energy
  3. A common emitter amplifier has a voltage gain of 50, an input impedance of 100Ω
  4. A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4
  5. Sound waves travel at 350m/s through a warm air and at 3500 m/s through brass

Topics: Thermodynamics (179)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*