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If the number of radius of ²⁷Al is 3.6 Fermi, the approximate nuclear radius of ⁶⁴Cu in Fermi is:
Options
(a) 2.4
(b) 1.2
(c) 4.8
(d) 3.6
Correct Answer:
4.8
Explanation:
The radius of the nuclears is directly proportional to cube root of atomic number i.e., R ∞ A¹/³
R = R₀A¹/³, where R₀ is a constant of proportionality
R₂ / R₁ = (A₂ / A₁)¹/³ (64 / 27)¹/³ = 4/3
where R₁ = radius of ²⁷Al, and A₁ = Atomic mass number of Al
R₂ = the radius of ⁶⁴Cu and A₂ = Atomic mass number of C4.
R₂ = 3.6 x 4/3 = 4.8 m.
Related Questions: - The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV
- Zenor breakdown in a semiconductor diode occurs when
- An astronomical telescope arranged for normal adjustment has a magnification of 6.
- The displacement of particle is given by x=aₒ+(a₁t/2)-(a₂t²/3) what is acceleration?
- A wire of resistance 4 ohm is stretched to twice its original length.
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV
- Zenor breakdown in a semiconductor diode occurs when
- An astronomical telescope arranged for normal adjustment has a magnification of 6.
- The displacement of particle is given by x=aₒ+(a₁t/2)-(a₂t²/3) what is acceleration?
- A wire of resistance 4 ohm is stretched to twice its original length.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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