| ⇦ | 
| ⇨ |
If the enthalpy change for the transition of liquid water to steam is 30 kJ mol⁻¹ at 27⁰C, the entropy change for the process would be
Options
(a) 10 J mol⁻¹ K⁻¹
(b) 1.0 J mol⁻¹ K⁻¹
(c) 0.1 J mol⁻¹ K⁻¹
(d) 100 J mol⁻¹ K⁻¹
Correct Answer:
100 J mol⁻¹ K⁻¹
Explanation:
We know that ΔG = ΔH – TΔS,
0 = ΔH -TΔS [ThereforeΔG=0],
ΔS = ΔH/T = 30 x 10³ / 300 = 100 J mol⁻¹ K⁻¹.
Related Questions: - Because of lanthanoid contraction,which of the following pairs of elements
- The change in oxidation state of sulphur when sulphur dioxide is passed
- Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
- Use of hot air balloons in sports and for meteorological observations is an application
- When sodium bicarbonate is heated strongly for calcined in a Kiln, it forms
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Because of lanthanoid contraction,which of the following pairs of elements
- The change in oxidation state of sulphur when sulphur dioxide is passed
- Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
- Use of hot air balloons in sports and for meteorological observations is an application
- When sodium bicarbonate is heated strongly for calcined in a Kiln, it forms
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply