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If the enthalpy change for the transition of liquid water to steam is 30 kJ mol⁻¹ at 27⁰C, the entropy change for the process would be
Options
(a) 10 J mol⁻¹ K⁻¹
(b) 1.0 J mol⁻¹ K⁻¹
(c) 0.1 J mol⁻¹ K⁻¹
(d) 100 J mol⁻¹ K⁻¹
Correct Answer:
100 J mol⁻¹ K⁻¹
Explanation:
We know that ΔG = ΔH – TΔS,
0 = ΔH -TΔS [ThereforeΔG=0],
ΔS = ΔH/T = 30 x 10³ / 300 = 100 J mol⁻¹ K⁻¹.
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Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Zeolite used to soften hardness of water is, hydrated
- What is the nature of the bond between B and O in (C₂H₅)₂ OBH₃?
- In the gas equation ,PV = nRT
- For which one of the following equations is ΔH⁰react equal to ΔH°f
- How many calories are required to heat 40 gram of argon from 40⁰C to 100⁰C
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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