| ⇦ |
| ⇨ |
If the energy of a photon is given as : =3.03 × 10⁻¹⁹J then, the wavelength (λ) of the photon is :
Options
(a) 6.56 nm
(b) 65.6 nm
(c) 656 nm
(d) 0.656 nm
Correct Answer:
656 nm
Explanation:
The energy of photon, E = hc /λ = 3.03 x 10⁻¹⁹ ⇒ λ = (6.626 x 10⁻³⁴ x 3 x 10⁸) / 3.03 x 10⁻¹⁹= 656 nm
Related Questions: - The oxidation of benzene by V₂O₅ in the presence of air produces
- Standard reduction potential for Al³⁺/Al , Fe²/Fe, Br/Br are ₋1.66V, ₋0.45V, 1.09V
- 1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide
- Oxidation state of iron in [Fe(H₂O)₅NO]SO₄ is
- Ferrocene is an example of
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The oxidation of benzene by V₂O₅ in the presence of air produces
- Standard reduction potential for Al³⁺/Al , Fe²/Fe, Br/Br are ₋1.66V, ₋0.45V, 1.09V
- 1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide
- Oxidation state of iron in [Fe(H₂O)₅NO]SO₄ is
- Ferrocene is an example of
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply