| ⇦ | 
| ⇨ |
If the energy of a photon is given as : =3.03 × 10⁻¹⁹J then, the wavelength (λ) of the photon is :
Options
(a) 6.56 nm
(b) 65.6 nm
(c) 656 nm
(d) 0.656 nm
Correct Answer:
656 nm
Explanation:
The energy of photon, E = hc /λ = 3.03 x 10⁻¹⁹ ⇒ λ = (6.626 x 10⁻³⁴ x 3 x 10⁸) / 3.03 x 10⁻¹⁹= 656 nm
Related Questions: - 2-phenylethylbromide when heated with NaOEt, elimination takes place.
- Which of the following statement about the member of any one homologous series
- Which of the following is obtained,when formaldehyde reacts with ammonia
- The bond dissociation energies of H₂, Cl₂ and HCl are 104, 58, and 103
- Difference in density is the basis of
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 2-phenylethylbromide when heated with NaOEt, elimination takes place.
- Which of the following statement about the member of any one homologous series
- Which of the following is obtained,when formaldehyde reacts with ammonia
- The bond dissociation energies of H₂, Cl₂ and HCl are 104, 58, and 103
- Difference in density is the basis of
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply