| ⇦ | 
| ⇨ |
If the energy of a photon is given as : =3.03 × 10⁻¹⁹J then, the wavelength (λ) of the photon is :
Options
(a) 6.56 nm
(b) 65.6 nm
(c) 656 nm
(d) 0.656 nm
Correct Answer:
656 nm
Explanation:
The energy of photon, E = hc /λ = 3.03 x 10⁻¹⁹ ⇒ λ = (6.626 x 10⁻³⁴ x 3 x 10⁸) / 3.03 x 10⁻¹⁹= 656 nm
Related Questions: - The combustion enthalpies of carbon , hydrogen and methane are -395.5 kJ mol⁻¹
- The hardest substance amongst the following is
- The pyknometric density of sodium chloride crystal is 2.165 x 10³ kg m⁻³,
- In graphide electrons are
- The oxidation number of sulphur is -1 in
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The combustion enthalpies of carbon , hydrogen and methane are -395.5 kJ mol⁻¹
- The hardest substance amongst the following is
- The pyknometric density of sodium chloride crystal is 2.165 x 10³ kg m⁻³,
- In graphide electrons are
- The oxidation number of sulphur is -1 in
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply