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If the electric field lines is flowing along axis of a cylinder, then the flux of this field through the cylindrical surface with the axis parallel to the field is [where r=radius of cylinder]
Options
(a) σ/2πrε₀
(b) σ/ε₀
(c) zero
(d) σ/2ε₀
Correct Answer:
zero
Explanation:
As we have to find the electric flux through the cylindrical surface and we are given that the electric field is flowing along axis of cylinder.
So as we draw area vector on cylindrical surface it will make an angle of 90• by which the cos 90 will become 0 and ans would be 0
Related Questions: - A radiation of energy ‘E’ falls normally on a perfectly reflecting surface
- Two charged spheres seperated at a distance d exert a force F on each other.
- A galvanometer coil has a resistance of 15 ohm and gives full scale deflection
- Consider two particles of different masses. In which of the following situations
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A radiation of energy ‘E’ falls normally on a perfectly reflecting surface
- Two charged spheres seperated at a distance d exert a force F on each other.
- A galvanometer coil has a resistance of 15 ohm and gives full scale deflection
- Consider two particles of different masses. In which of the following situations
- Four identical cells of emf Ԑ and internal resistance r are to be connected in series.
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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As we have to find the electric flux through the cylindrical surface and we are given that the electric field is flowing along axix of cylinder
So as we draw area vector on cylindrical surface it will make an angle of 90• by which the cos 90 will become 0 and ans would be 0
Thanks (Prateekpreet Madhukar)