| ⇦ | 
| ⇨ |
If the electric field lines is flowing along axis of a cylinder, then the flux of this field through the cylindrical surface with the axis parallel to the field is [where r=radius of cylinder]
Options
(a) σ/2πrε₀
(b) σ/ε₀
(c) zero
(d) σ/2ε₀
Correct Answer:
zero
Explanation:
As we have to find the electric flux through the cylindrical surface and we are given that the electric field is flowing along axis of cylinder.
So as we draw area vector on cylindrical surface it will make an angle of 90• by which the cos 90 will become 0 and ans would be 0
Related Questions: - The moon’s radius is 1/ 4 that of the earth and its mass is 1 / 80 times that of the earth
- A satellite is launched into a circular orbit of radius R around earth while
- A small oil drop of mass 10⁻⁶kg is hanging in at rest between two plates seperated
- A tyre filled with air (27° C and 2 atm) bursts. The temperature of air is (ˠ=1.5)
- When a p-n junction is reverse biased, then the current through the junction
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The moon’s radius is 1/ 4 that of the earth and its mass is 1 / 80 times that of the earth
- A satellite is launched into a circular orbit of radius R around earth while
- A small oil drop of mass 10⁻⁶kg is hanging in at rest between two plates seperated
- A tyre filled with air (27° C and 2 atm) bursts. The temperature of air is (ˠ=1.5)
- When a p-n junction is reverse biased, then the current through the junction
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
As we have to find the electric flux through the cylindrical surface and we are given that the electric field is flowing along axix of cylinder
So as we draw area vector on cylindrical surface it will make an angle of 90• by which the cos 90 will become 0 and ans would be 0
Thanks (Prateekpreet Madhukar)