| ⇦ |
| ⇨ |
If the dipole moment of a short bar magnet is 1.25 A-m², the magnetic field on its axis at a distance of 0.5 m from the centre of the magnet is
Options
(a) 1×10⁻⁴ NA⁻¹ m⁻¹
(b) 2×10⁻⁶NA⁻¹ m⁻¹
(c) 4×10⁻²NA⁻¹ m⁻¹
(d) 6.64×10⁻⁸NA⁻¹ m⁻¹
Correct Answer:
2×10⁻⁶NA⁻¹ m⁻¹
Explanation:
The magnetic field at a point on the axis of a bar magnet is, B = 2μ₀M / 4πr³
= 10⁻⁷ × [(2×1.25) / (0.5)³] = 2 x 10⁻⁶ NA⁻¹ m⁻¹
Related Questions: - Two bodies A and B having temperature 327° C and 427° C are radiating heat
- The number of NAND gates required to form an AND gate is
- The distance travelled by a particle starting from rest and moving with an acceleration
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- The acceleration due to gravity at a place is π² m/sec². Then the time period
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies A and B having temperature 327° C and 427° C are radiating heat
- The number of NAND gates required to form an AND gate is
- The distance travelled by a particle starting from rest and moving with an acceleration
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- The acceleration due to gravity at a place is π² m/sec². Then the time period
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply