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If the dipole moment of a short bar magnet is 1.25 A-m², the magnetic field on its axis at a distance of 0.5 m from the centre of the magnet is
Options
(a) 1×10⁻⁴ NA⁻¹ m⁻¹
(b) 2×10⁻⁶NA⁻¹ m⁻¹
(c) 4×10⁻²NA⁻¹ m⁻¹
(d) 6.64×10⁻⁸NA⁻¹ m⁻¹
Correct Answer:
2×10⁻⁶NA⁻¹ m⁻¹
Explanation:
The magnetic field at a point on the axis of a bar magnet is, B = 2μ₀M / 4πr³
= 10⁻⁷ × [(2×1.25) / (0.5)³] = 2 x 10⁻⁶ NA⁻¹ m⁻¹
Related Questions: - If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
- A solid cylinder of mass M and radius R rolls without slipping down and inclined plane
- A current I flows along the length of an infinitely long, straight, thin walled pipe.
- A solid which is transparent to visible light and whose conductivity increases
- A transformer having efficiency of 90% is working on 200 V and 3kW power supply
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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