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If the dipole moment of a short bar magnet is 1.25 A-m², the magnetic field on its axis at a distance of 0.5 m from the centre of the magnet is
Options
(a) 1×10⁻⁴ NA⁻¹ m⁻¹
(b) 2×10⁻⁶NA⁻¹ m⁻¹
(c) 4×10⁻²NA⁻¹ m⁻¹
(d) 6.64×10⁻⁸NA⁻¹ m⁻¹
Correct Answer:
2×10⁻⁶NA⁻¹ m⁻¹
Explanation:
The magnetic field at a point on the axis of a bar magnet is, B = 2μ₀M / 4πr³
= 10⁻⁷ × [(2×1.25) / (0.5)³] = 2 x 10⁻⁶ NA⁻¹ m⁻¹
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For non-conductors, the energy gap is
- In an a.c circuit the e.m.f. (e) and the current (i) at any instant are given
- A body revolved around the sun 27 times faster than the earth. What is the ratio
- A transformer of 100% efficiency has 200 turns in the primary coil and 40000 turns
- A 0.5 kg ball moving with a speed of 12 m/s strikes a hard wall at an angle
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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