IF the bond energies of H – H , Br – Br and H – Br are 433 , 192 and 364 kJ mol⁻¹

⇦

⇨

IF the bond energies of H – H , Br – Br and H – Br are 433 , 192 and 364 kJ mol⁻¹ respectively, the ΔH° for the reaction
H₂(g) + Br₂(g) → 2HBr(g) is

Options

(a) -261 kJ
(b) ⁺103 kJ
(c) ⁺261 kJ
(d) -103 kJ

Correct Answer:

-103 kJ

Explanation:

H – H + Br – Br → 2H – Br,
(433) + (192) (2 x 364)
=625 =728
(Energyabsorbed) (Energy released)
Net energy released = 728 – 625 = 103 KJ. i.e. ΔH = -103 KJ.

Related Questions:

1. When a strong beam of light is passed through a colloidal solution, the light will
2. The number of hydroxide ions produced by one molecule of sodium carbonate
3. H₂S is not a
4. Atoms in a P₄ molecule of white phosphorus are arranged regularly in the follow
5. The long form of periodic table is based on

Topics: Thermodynamics (179)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends