| ⇦ | 
| ⇨ |
If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy required to remove the electron from the first excited state of Li⁺⁺ is
Options
(a) 122.4 eV
(b) 30.6 eV
(c) 13.6 eV
(d) 3.4 eV
Correct Answer:
30.6 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If A=4i+4j+4k and b=3i+j+4k, then angle between vectors A and B is
- The velocity of image when object and mirror both are moving towards each other
- An electron revolves in a circle at the rate of 10¹⁹ rounds per second.
- The value of Planck’s constant is
- An α-particle and a proton are accelerated through same potential difference
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If A=4i+4j+4k and b=3i+j+4k, then angle between vectors A and B is
- The velocity of image when object and mirror both are moving towards each other
- An electron revolves in a circle at the rate of 10¹⁹ rounds per second.
- The value of Planck’s constant is
- An α-particle and a proton are accelerated through same potential difference
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply