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If radius of the ₁₃Al²⁷ nucleus is taken to be Rᴀı, then the radius of ₅₃Te¹²⁵ nucleus is nearly
Options
(a) (53/13)¹⁄₃ Rᴀı
(b) 5/3Rᴀı
(c) 3/5Rᴀı
(d) (13/53)¹⁄₃ Rᴀı
Correct Answer:
5/3Rᴀı
Explanation:
Radius of the nucleus is given by,
R = R₀A¹/³ ⇒ R ∝ A¹/³
.·. Rᴀ₁ / Rᴛₑ = [Aᴀ₁ / Aᴛₑ]¹/³ = [27 / 125]¹/³ = 3 / 5
Rᴛₑ = (5 / 3) Rᴀ₁
Related Questions: - Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
- A black body radiates 20 W at temperature 227⁰C. It temperature of the black body
- Which of the following phenomenon exhibited the particle nature of light?
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
- A black body radiates 20 W at temperature 227⁰C. It temperature of the black body
- Which of the following phenomenon exhibited the particle nature of light?
- For an ideal gas of diatomic molecules
- Two point charges +2 coulomb and +10 coulomb repel each other with a force of 12 N.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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