| ⇦ |
| ⇨ |
If Q, E and W denote respectively the heat added, change in internal energy and the work done in a closed cyclic process, then:
Options
(a) W = 0
(b) Q = W = 0
(c) E = 0
(d) Q = 0
Correct Answer:
E = 0
Explanation:
In a cyclic process, the initial state coincides with the final state. hence, the change in internal energy is zero, as it depends only on the initial and final states. But Q and W are non-zero during a cycle process.
Related Questions: - Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart
- Initial pressure and volume of a gas are P and 800cc. If the final volume is 100cc
- To observed diffraction, the size of the obstacle
- A long solenoid has 500 turns. When a current of 2 ampere is passed through it
- Starting from the origin, a body oscillates simple harmonically with a period of 2s
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart
- Initial pressure and volume of a gas are P and 800cc. If the final volume is 100cc
- To observed diffraction, the size of the obstacle
- A long solenoid has 500 turns. When a current of 2 ampere is passed through it
- Starting from the origin, a body oscillates simple harmonically with a period of 2s
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply