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If pH of a saturated solution of Ba(OH)₂ is 12, the value of its Ksp is
Options
(a) 4.00 ˣ 10⁻⁶ M³
(b) 4.00 ˣ 10⁻⁷ M³
(c) 5.00 ˣ 10⁻⁶ M³
(d) 5.00 ˣ 10⁻⁷ M³
Correct Answer:
5.00 ˣ 10⁻⁷ M³
Explanation:
We Know, pH + pOH = 14,
Here, 12 + pOH = 14,
pOH = 2,
⇒ [OH⁻] = 10⁻².
Ba(OH)₂ ⇌ Ba²⁺ + 2OH⁻.
2s = [OH⁻] = 10⁻².
s = 10⁻²/2 = 5×10⁻³ M.
K(sp) = [Ba²⁺][OH⁻]² = (5×10⁻³)(10⁻²)²,
K(sp) = 5×10⁻⁷.
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Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
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