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If pH of a saturated solution of Ba(OH)₂ is 12, the value of its Ksp is
Options
(a) 4.00 ˣ 10⁻⁶ M³
(b) 4.00 ˣ 10⁻⁷ M³
(c) 5.00 ˣ 10⁻⁶ M³
(d) 5.00 ˣ 10⁻⁷ M³
Correct Answer:
5.00 ˣ 10⁻⁷ M³
Explanation:
We Know, pH + pOH = 14,
Here, 12 + pOH = 14,
pOH = 2,
⇒ [OH⁻] = 10⁻².
Ba(OH)₂ ⇌ Ba²⁺ + 2OH⁻.
2s = [OH⁻] = 10⁻².
s = 10⁻²/2 = 5×10⁻³ M.
K(sp) = [Ba²⁺][OH⁻]² = (5×10⁻³)(10⁻²)²,
K(sp) = 5×10⁻⁷.
Related Questions: - The solubility of BaSO₄, in water, is 2.33 ˣ 10⁻³ g/L.Its solubility product
- Total number of isomers possible for the molecular formula C₄H₁₀O is
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Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The solubility of BaSO₄, in water, is 2.33 ˣ 10⁻³ g/L.Its solubility product
- Total number of isomers possible for the molecular formula C₄H₁₀O is
- Among the following the compound that is readily soluble in water is
- When iodine is dissolved in CCl₄, the resulting colour is
- Certain bimolecular reactions which following first order kinetics are called
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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