If pH of a saturated solution of Ba(OH)₂ is 12, the value of its Ksp is

⇦

⇨

If pH of a saturated solution of Ba(OH)₂ is 12, the value of its Ksp is

Options

(a) 4.00 ˣ 10⁻⁶ M³
(b) 4.00 ˣ 10⁻⁷ M³
(c) 5.00 ˣ 10⁻⁶ M³
(d) 5.00 ˣ 10⁻⁷ M³

Correct Answer:

5.00 ˣ 10⁻⁷ M³

Explanation:

We Know, pH + pOH = 14,
Here, 12 + pOH = 14,
pOH = 2,
⇒ [OH⁻] = 10⁻².
Ba(OH)₂ ⇌ Ba²⁺ + 2OH⁻.

2s = [OH⁻] = 10⁻².
s = 10⁻²/2 = 5×10⁻³ M.
K(sp) = [Ba²⁺][OH⁻]² = (5×10⁻³)(10⁻²)²,
K(sp) = 5×10⁻⁷.

Related Questions:

1. The unit of rate constant depends upon
2. Which of the following alcohol is least soluble in water
3. If the equivalent weight of an element is 32, then the percentage of oxygen
4. In which of the following compounds, carbon exhibits a valency of 4
5. Which one of the following gives only one monochloro derivative

Topics: Equilibrium (104)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends